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Two particles A and B of masses 1kg and 2kg respectively are projected in the directions shown in figure with speeds `u_A=200m//s` and `u_B=50m//s`. Initially they were `90m` apart. They collide in mid air and stick with each other. Find the maximum height attained by the centre of mass of the particles. Assume acceleration due to gravity to be constant.
`(g=10m//s^2)`

A

`115.55m`

B

`145.55m`

C

`4.55 m`

D

`34.55 m`

Text Solution

Verified by Experts

The correct Answer is:
A

Maximum height attained by `C.M`
=Initial heigh of `C.M. +(u_(cm)^(2))/(2g)`
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