A uniform circular disc of radius `R` lies in the `XY` plane with its centre coinciding with the origin.The moment of inertia about an axis passing through a point on the X-axis at a distance `x=2R` and perpendicular to the X-Y plane is equal to its moment of inertia about an axis passing through a point on the Y-axis at a distance `y=d` and parallel to the X-axis in the X-Y plane. The value of `d` is

Options

A. `(sqrt(19))/2 R`
B. `(sqrt(17))/2 R`
C. `(sqrt(15))/2 R`
D. `(sqrt(13))/2 R`

Answer

C

Explanation

`I_(1)=(mR^(2))/4+m(2R)^(2), I_(2)=(mR^(2))/2+md^(2),I_(1)=I_(2)`