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A shaft is turning at 65rad//s at time z...

A shaft is turning at `65rad//s` at time zero. Thereafter, angular acceleration is given by `alpha=-10rad//s^(2)-5trad//s^(2)`
Where `t` is the elapsed time
(a). Find its angular speed at `t=3.0` s
(b). How much angle does it turn in these `3s`?

A

`25 rad//sec`

B

`12.5 rad//sec`

C

`17 rad//sec`

D

`22 rad//sec`

Text Solution

Verified by Experts

The correct Answer is:
B
`omega=intalphadt`
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