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A uniform rod of length L and mass M is ...

A uniform rod of length `L` and mass `M` is pivoted freely at one end and placed in vertical position.
a. What is angular acceleration of the rod when it is at an angle `theta` with the vertical?
b. What is the tangential linear acceleration of the free end when the rod is horizontal?

A

`g/2`

B

`(3g)/2`

C

`g/3`

D

`(2g)/3`

Text Solution

Verified by Experts

The correct Answer is:
B
`tau=(mgl)/2 sin theta, alpha=(3g sin theta)/(2l)`
When rod is horizontal `theta=(pi)/2`
`:. Alpha=(3g)/(2l) rArra_(1)=alphal=(3g)/2`
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