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In Fig. the velocities are in ground fra...

In Fig. the velocities are in ground frame and the cylinder is performing pure rolling on the plank, velocity of point `'A'` would be

A

`2V_(C)`

B

`2V_(C)-C_(P)`

C

`2V_(C)+V_(P)`

D

`2(V_(C)-V_(P))`

Text Solution

Verified by Experts

The correct Answer is:
B
`V_(C)-romega=Vp to (1)`
`V_(A)=V_(C)+r omega=2V_(C)-Vp`
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