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A uniform circular ring of radius R is f...

A uniform circular ring of radius `R` is first rotated about its horizontal axis with an angular velocity `omega_0` and then carefully placed on a rough horizontal surface as shown. The coefficient of friction between the surface and the rings `mu`. Time after which its angular speed is reduced to `0.5 omega_0` is

A

`(omega_(0)muR)/(2g)`

B

`(omega_(0)g)/(2muR)`

C

`(2 omega_(0)R)/(mug)`

D

`(omega_(0)R)/(2mug)`

Text Solution

Verified by Experts

The correct Answer is:
D
Taking the `tau` about `C.M.`
`mu mG R=MR^(2)alpha,mug=RalpharArralpha=(mug)/R`
`omega=omega_(0)-(mug)/Rt=(omega_(0))/2, :. T=(omega_(0)R)/(2mug)`
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