A particle of mass `'m'` is rigidly attached at `'A'` to a ring of mass `3m` and radius `'r'` . The system is released from rest and rolls without sliding. The angular release is acceleration of ring just after release after

Options

A. `g/(4r)`
B. `g/(6r)`
C. `g/(8r)`
D. `g/(2r)`

Answer

B

Explanation

The distance of `CM` from the ring centre `O`
`x=(3m(0)+m(r))/(3m+m)=r/4`
we can apply torque equation about point of contanct as the ring is rolling

`4mg(r/4)=[(3mr^(2)+mr^(2))+m(AP)^(2)]alpha`
`rArrmgr=[4mr^(2)+m(sqrt(2)r)^(2)]alpha`
`rArrmgr=6mr^(2)alpharArra=g/(6r)`