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The handle of a door is at a distance 40...

The handle of a door is at a distance `40cm` from axis of rotation. If a force `5N` is applied on the handle in a direction `30^@` with plane of door, then the torque is

A

`0.8 Nm`

B

`1 Nm`

C

`1.6 Nm`

D

`2Nm`

Text Solution

Verified by Experts

The correct Answer is:
B
`tau =r F sin theta`
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