A particle of mass m is projected with s...

A particle of mass m is projected with speed u at an angle `theta` with the horizontal. Find the torque of the weight of the particle about the point of projection when the particle is at the highest point.

`(mgu^(2)sin 2 theta)/2`

`mgu^(2)sin 2 theta`

`(mgu^(2)sin theta)/2`

`1/2 m u^(2)sin 2 theta`

Text Solution

Verified by Experts

The correct Answer is:

`vec(tau)=[R/2hati+Hhatj]xxmghatj`

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