A wire of mass `m` and length `l` is bent in the form of circular ring. The moment of inertia of the ring about its axis is

Options

A. `ml^(2)`
B. `(ml^(2))/(4pi^(2))`
C. `(ml^(2))/(2pi^(2))`
D. `(ml^(2))/(8pi^(2))`

Answer

B

Explanation

`I=mr^(2),r=l/(2pi)`