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A particle of mass m is moving in a plan...

A particle of mass `m` is moving in a plane along a circular path of radius `r`. Its angular momentum about the axis of rotation is `L`. The centripetal force acting on the particle is.

A

`(L^(2))/(mr)`

B

`(L^(2)m)/r`

C

`(L^(2))/(mr^(2))`

D

`(L^(2))/(mr^(2))`

Text Solution

Verified by Experts

The correct Answer is:
D

`L=mvrrArrv=L/(mr)`
centripetal force `F=(mv^(2))/r=(L^(2))/(mr^(3))`
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