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A mass is whirled in a circular path wit...

A mass is whirled in a circular path with an angular momentum `L`. If the length of string is now halved keeping the angular velocity same, the new angular momentum is

A

`L//4`

B

`L//2`

C

`L`

D

`2L`

Text Solution

Verified by Experts

The correct Answer is:
A
`L=mr^(2)omega,L propr^(2), (L_(1))/(L_(2))=((r_(1))/(r_(2)))^(2)rArrL_(2)=L/4`
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