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For a body rolling along a level surface...

For a body rolling along a level surface, without slipping the translational and rotational kinetic energies are in the ratio `2:1`. The body is

A

Hollow sphere

B

solid cylinder

C

ring

D

solid sphere

Text Solution

Verified by Experts

The correct Answer is:
B
`(1/2mV^(2))/(1/2Iomega^(2))=2/1`
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Knowledge Check

  • For a body rolling along a level surface, the translational and rotational K.E. are equal. The body is

    A
    solid cylinder
    B
    disc
    C
    ring
    D
    hollow sphere

  • If a rigid body rolls on a surface without slipping, then:

    A
    linear speed is maximum at the highest point but minimum at the point of contact
    B
    linear speed is minimum at highest point but maximum at the point of contact
    C
    linear speed is same at all points of the rigid body
    D
    angular speed is different at different points of a rigid body

  • A disc is rolling on a surface without slipping. What is the ratio of its translational to rotational kinetic energies ?

    A
    `5 : 2`
    B
    `1 : 1`
    C
    `3 : 2`
    D
    `2 : 3`

    • Similar Questions

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