A ring of mass `m` and radius `R` is rolling down on a rough inclined plane of angle `theta` with horizontal. Plot the angular momentum of the ring about the point of contact of ring and the plane as a function of time

Options

A.
B.
C.
D.

Answer

D

Explanation

`L=(mg sin theta)Rt`, since , `tau=(DeltaL)/(Deltat)`, so, `L=tau(Deltat)`
The curve between `L` and time `t` will be a straight line.