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Two identical rings A and B are acted up...

Two identical rings A and B are acted upon by torques `tau_(A)` and `tau_(B)` respectively. A is rotating about an axis passing through the centre of mass and perpendicular ot the plane of the ring. B is rotating about a chord at a distance `1/(sqrt(2))` times the radius of the ring. If the angular acceleration of the ring is the same, then

A

`tau_(A)=tau_(B)`

B

`tau_(A)gttau_(B)`

C

`tau_(A)lttau_(B)`

D

nothing can be said about `tau_(A)` and `tau_(B)` as data are insufficient

Text Solution

Verified by Experts

The correct Answer is:
A

`I'_(B)`(in new given condition)
`=1/2MR^(2)+M(R/(sqrt(2))^(2))=MR^(2)=I_(A)`
thus, `tau_(A)=tau_(B)=tau_(B)'=Ialpha`
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