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A uniform solid sphere of radius r is ro...

A uniform solid sphere of radius `r` is rolling on a smooth horizontal surface with velocity `v` and angular velocity `omega = (v=omega r)`. The sphere collides with a sharp edge on the wall as shown in figure. The coefficient of friction between the sphere and the edge `mu=1//5`. Just after the collision the angular velocity of the sphere becomes equal to zero. The linear velocity of the surface just after the collision is equal to

A

`V`

B

`V/5`

C

`(3v)/5`

D

`(2V)/5`

Text Solution

Verified by Experts

The correct Answer is:
A


`intNdt`
`-intNdt=-mV'-(mV)......(1)`
`muRintNdt=2/5mR^(2)(V/R)......(2)`
From eqns,. (1)and (2), we get
`intNdt=2mV` and `V'=V`
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