The end B of the rod AB which makes angle `theta` with the floor is being pulled with a constant velocity `v_(v)` as shown. The length of the rod is `l`.

Options

A. velocity of end `A` is `2/3 V_(0)` downwards
B. angular velocity of rod is `5/3 (V_(0))/l`
C. angular velocity of rod is constant
D. velocity of end `A` is constant

Answer

B

Explanation

This equations is on example of combination rotational and translational motion, here we are solving this with the help of instantaneous axis of rotation is lying at a distance of `l sin theta` from end `B` and perpendicular to `V_(0)`. Let `omega` is the angular velocities of rod. then.
`V_(A)=omegaxxl cos theta`
and `V_(B)=V_(0)=omegaxxl sin theta`