The pulley shown in figure has a radius 10 cm and moment of inertia 0.5 kg-m^2 about its axis. Assuming the inclined planes to be frictionless, calculate the acceleration of the 4.0 kg block.

Answer

4

Explanation

`(T_(1)-T_(1))R=Ialpha`
`(T_(2)-T_(1))R=I(a/R)to(i)`
`4g sin 45^(@)-T_(2)=4ato(ii)`
`T_(1)=2g sin 45^(@)=2ato(iii)`
Solving (i), (ii),(iii) we get `a=0.25 m//s^(2)`