The adjacent graph shows the estension `(Deltal)` of a wire of length 1m suspended from the top of a roof at one end and with a load W connected to the other end. If the cross-sectional area of the wire is `10^-6m^2`, calculate the Young's modulus of the material of the wire.

Explanation

From graph, slope `= (e)/(W) = (1)/(20) xx 10^(-4)`
or `(W)/(e) = (F)/(e) = 20xx10^(44), Y = (F)/(A) xx (l)/(e) = ((W)/(e)) xx (l)/(A)`
`= 20xx10^(4) xx (1)/(10^(-6)) = 2xx10^(11) N//m^(2)`