A copper wire `2m` long is stretched by `1mm`. If the energy strored in the stretched wire is converted into heat, then calculate the rise in temperature of the wire.

Explanation

`m s Delta t = (1)/(2) Y ("strain")^(2) xx (m)/(p)`
`Delta t = (1)/(2) xx (Y)/(s rho) xx ((e)/(l))^(2)`
`Delta t = (1)/(2) xx (12.5xx10^(10))/(9xx10^(3)xx385) xx [(1)/(1000xx2)]^(2) = 0.0045^(@)C`
So the rise in tempertuare of the wire is `0.0045^(@)C`