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A brass rod of cross sectional area 1cm^...

A brass rod of cross sectional area `1cm^2` and length `0.2m` is compressed lengthwise by a weight of `5kg`. If Young's modulus of elasticity of brass is `1xx10^(11)(N)/(m^2)` and `g=10(m)/(sec^2)` Then increase in the energy of the ro will be

A

increases by `2.4xx10^(-5) J`

B

decreases by `2.4xx 10^(-5)J`

C

increases by `2.4xx10^(7) J`

D

increases by `2.4xx10^(7) J`

Text Solution

Verified by Experts

The correct Answer is:
A
`E = (1)/(2) F xx e, e = (F)/(A) (l)/(Y)`
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