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What is the density of lead under a pres...

What is the density of lead under a pressure of `2.0xx10^(8) N//m^(2) ` , if the bulk modulus of lead is ` 8.0xx10^(9) N//m^(2)` and initially the density of lead is `11.4 g//cm^(3)`?

A

`12.89gm//cm^(3)`

B

`14gm//cm^(3)`

C

`11.69gm//cm^(3)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C
The changed density `rho = (rho)/(1 - (dp)/(B))`
substituing the value, we have `rho = 11.69g//cm^(3)`
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