How does the density of sea water change with depth?

Options

A. `(B rho^(2))/(gh)`
B. `B rho gh`
C. `(rho^(2)gh)/(B)`
D. `(rhogh)/(B)`

Answer

C

Explanation

Change in pressure `Delta P = rho g h`
Bulk modulus `B = (-Delta P)/(Delta V//V), (Delta V)/(V) = (-Delta rho)/(rho)`
`therefore Delta rho = (rho Delta P)/(B) = (rho (rho g h))/(B) = (rho^(2) gh)/(B)`