When the tension on a wire is `4N` its length is `l_(1)`. When the tension on the wire is `4N` length is `l_(1)`. When the tension on the wire is `5N` its length is `l_(2)`. Find its natural length.

Options

A. `5l_(1) - 4l_(2)`
B. `4l_(1) - 5l_(2)`
C. `10l_(1) - 8l_(2)`
D. `8l_(1) - 10l_(2)`

Answer

A

Explanation

`(l_(1) - l)/(l_(2 - l) = (T_(1))/(T_(2))`