A tangential force of `2100N` is applied on a surface area `3xx10^(-6) m^(2)` which is `0.1m` form fixed surface. The force produces a shift of `7m` of upper surface with respect to bottom. Calcualte the modulus of rigidity fo the material.

Options

A. `2xx10^(10) N//m^(2)`
B. `1xx10^(10) N//m^(2)`
C. `3xx10^(10) N//m^(2)`
D. `4xx10^(10) N//m^(2)`

Answer

B

Explanation

`eta = (F)/(A) (L)/(Delta x)`