When a wire of length `10m` is subjected to a force of `100N` along its length, the lateral strain produced is `0.01xx10^(-3)`. The poisson's ratio was found to be `0.4`. If area of cross section of wire is `0.25 m^(2)`, its young's modulus is

Options

A. `1.6xx10^(8)N//m^(2)`
B. `2.5xx10^(10) N//m^(2)`
C. `12.5xx10^(11) N//m^(2)`
D. `16xx10^(9) N//m^(2)`

Answer

A

Explanation

`sigma = (-((Delta r)/(r)))/(((Delta l)/(l))), Y = (Fl)/(Ae)`