A small ball of density `rho` is immersed in a liquid of density `sigma(gtrho)` to a depth `h` and released. The height above the surface of water up to which the ball will jump is

Explanation

Volume of ball `V=(m)/(rho)`
Acceleration of ball moving in upward direction inside the liquid.
`a=(F_("net"))/(m)=("upthrust-weight")/(m)=(V_("total")rho_(1)g-mg)/(m)`
`a=(((m)/(rho))(3rho)(g)-mg)/(m)=2g` (upwards)
`:.` velocity of ball while crossing the surface
`v=sqrt(2ah)=sqrt(4gh)`
`:.` the ball will jump to a height
`H=(v^(2))/(2g)=(4gh)/(2g)=2h`