A `16cm^(3)` of water flows per second through a capillary tube of radius `r` cm and of length 1 cm, when connected to a pressure head of `h` cm of water. If a tube of the same length and radius `r//2` is connected to the same pressure head, find the mass of watear flowing per minute through the tube.

Explanation

`Vprop(Pr^(4))/(l)implies(V_(2))/(V_(1))=(P_(2))/(P_(1))xx(r_(2)^(4))/(r_(1)^(4))xx(l_(1))/(l_(2))`
`=((r//2)^(4))/(r^(4))xx(l)/(l)=((1)/(2))^(4)=(1)/(16),V_(2)=(16)/(16)=1(cm^(3))/(s)` volume of water flowing per minute
`=1xx60=60 cm^(3)//min`
Mass of water flowing per minute
`=Vxxd=60xx1=60gram//min`.