Water flows in a streamline manner through a cappilary tube of radius a. The pressure difference being P and the rate of flow is Q . If the radius is reduced to `a//2` and the pressure difference is increased to 2P, then find the rate of flow.

Explanation

To solve the problem, we will use the formula for the rate of flow (Q) through a capillary tube, which is given by Poiseuille's law:

\[ Q = \frac{\pi \Delta P \cdot r^4}{8 \eta l} \]

where:
- \(Q\) = rate of flow
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