A water drop of diameter 2 mm is split up into `10^(9)` identical water drops. Calculate the work done in this process. (the surface tension of water is `7.3xx10^(-2)Nm^(-1))`

Explanation

To solve the problem of calculating the work done when a water drop of diameter 2 mm is split into \(10^9\) identical water drops, we can follow these steps:

### Step 1: Determine the radius of the initial drop
The diameter of the initial drop is given as 2 mm. Therefore, the radius \( R \) can be calculated as:
\[ R = \frac{\text{Diameter}}{2} = \frac{2 \, \text{mm}}{2} = 1 \, \text{mm} = 1 \times 10^{-3} \, \text{m} \]

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