A U tube is supported with its limbs vertical and is partly filled with water. If the inner diameter of the limbs are 1cm,and 0.01 cm , respectively, what will be the difference in height of water in the two limbs? S.T. or water `70 xx 10^(-3) Nm^(-1)`. Angle of contact , `theta = 0^(@)`.

Explanation

Surface tension ,`T=0.07Nm^(-1)`,
Density `d=1000kgm^(-3),g=9.8ms^(-2)`
angle of contact `theta=0^(0)`
Radius `r_(1)=0.5xx10^(-2)m`, radius `r_(2)=0.5xx10^(-4)m`
Then,
`h=(2T)/(dg)((1)/(r_(1))-(1)/(r_(2)))`
`=(2xx0.07)/(10^(3)xx9.8)((1)/(0.5xx10^(-2))-(1)/(0.5xx10^(-4)))=0.283m`