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A bird of mass 1.23 kg is able to haver ...

A bird of mass 1.23 kg is able to haver by imparting a downward velocity of `10 m//s` uniformly to air of density `rho kg//m^(3)` over an effective area `0.1m^(2)` the acceleration due to gravity is `10m//s^(2)` then the magnitude of `rho` in `kg//m^(3)`

A

`0.34`

B

`0.89`

C

`1.23`

D

`4.8`

Text Solution

Verified by Experts

The correct Answer is:
C
Weight of bird `=` force excted by the bird by moving its wings `rhoAu^(2)=mg (F=Au^(2)rho)`
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Knowledge Check

  • The r.m.s. velocity of molecules of a gas of density 4 kg m^(-3) and pressure 1.2xx10^(5)Nm^(-2) is

    A
    `900 ms^(-1)`
    B
    `120 m s^(-1)`
    C
    `600 m s^(-1)`
    D
    `300 m s^(-1)`

  • At a given place where acceleration due to gravity is g m/s^2 , a sphere of lead density d kg/m^3 . If d gt rho , the sphere will

    A
    fall vertically with an acceleration `g m/s^2`
    B
    fall vertically with no acceleration
    C
    fall vertically with an acceleration `g ((d-rho)/d)`
    D
    fall vertically with an acceleration `g (rho/d)`

  • At a given place where acceleration due to gravity is g m/s^2 , a sphere of lead density d kg/m^3 . If d gt rho , the sphere will

    A
    fall vertically with an acceleration `g m/s^2`
    B
    fall vertically with no acceleration
    C
    fall vertically with an acceleration `g ((d-rho)/d)`
    D
    fall vertically with an acceleration `g (rho/d)`
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