The level of a liquid in a vessel kept constant at 50 cm. it has three identical horizontal tubes each of length 60 cm coming out at heights 5,10 and 15 cm respectively. If a single tube of the same radius as that of the three tubes can replace the three tubes when placed horizontaly at the bottom of the vessel length of that tube is

Options

A. 25 cm
B. 40 cm
C. 12.5 cm
D. 50 cm

Answer

A

Explanation

`(piPr^(4))/(8etal)=(piP_(1)r^(4))/(8etal_(1))+(piP_(2)r^(4))/(8etal_(2))+(piP_(3)r^(4))/(8etal_(3))`
`(H)/(L)=(H-h_(1))/(8etal_(1))+(H-h_(2))/(l)+(H-h_(2))/(l)`
`(50)/(L)=(45)/(60)+(40)/(60)+(35)/(60)impliesL=25cm`