Water rises to a height h(1) in a capill...

Water rises to a height `h_(1)` in a capillary tube in a stationary lift. If the lift moves up with uniform acceleration it rises to a height `h_(2)`, then acceleration of the lift is

A

`[(h_(2)-h_(2))/(h_(2))]g`

B

`[(h_(2)-h_(1))/(h_(1))]g`

C

`[(h_(1)-h_(2)))/(h_(1))]g`

D

`[(h_(1)-h_(2))/(h_(2))]g`

Text Solution

Verified by Experts

The correct Answer is:

D

`h_(2)(g+a)=h_(1)g`

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