A tank of height `H` and base area `A` is half filled with water and there is a small orifice at the bottom and there is a heavy solid cylinder having base area `(A)/(3)` and height of the cylinder is same as that of the tak. The water is flowing out of the orifice. Here cylinder is put into the tank to increase the speed of water flowing out.
The speed of water flowing out of the orifice after the cylinder is kept inside it is

Options

A. `sqrt((gH)/(2))`
B. `sqrt((3gH)/(2))`
C. `sqrt(2gH)`
D. `sqrt(3gH)`

Answer

B

Explanation

Let `h` be the height of water column just after
putting cylinder `(A-(A)/(3))h^(')=(H)/(2)Aimpliesh^(')=(3H)/(4)`.
` :. vartheta=sqrt(2gh^(1))=sqrt((3gH)/(2))`