Excess pressure can be `(2T//R)` for

Options

A. spherical drop
B. spherical meniscus
C. clindrical bubble in air
D. spherical bubble in water

Answer

A, B, C, D

Explanation

i. Excess pressure inside a spherical liquid drop `(2T)/(R)` because there is only one free surface here
(ii). In case of spherical meniscus of radius of curvature R, also excess pressure `=(2T)/(R)` because again there is only one free surface.
(iii). Excess pressure inside a cylindrical drop of radius `R=(T)/(R)`, hence, for a culindrical bubble in air, excess pressure is `(2T)/(R)` because there exists two free surface `=(T)/(R)` in this case
(iv). for a spherical bubble in water, excess pressure `=(T)/(R)`, as there is only one free surface. Hence, all the four optional are correct.