Figure shows a capillary tube of radius r dipped into water. The atmospheric pressure is `P_(0)` and the capillary rise of water is `h`. `s` is the surface tension for water-glass.

Initially, `h = 10 cm`. If the capillary tube is now incline at `45^@`, the length of water rising in the tube will be

Options

A. 10 cm
B. `10sqrt(2)cm`
C. `(10)/(sqrt(2))`
D. `P_(0)-(4s)/(r)`

Answer

B

Explanation

When the capillary tube is tilted by an angle `theta` with the vertical the capillary rise to distance `l` in the tube will be such that the meniscus will remain at the same vertical height above the level of water in the container.
Hence, `h=lcostheta`
`l=(h)/(costheta)=(10)/(cos45^(@))=10sqrt(2)m`