A body cools from `80^(@)C` to `50^(@)C` in 5 minutes Calculate the time it takes to cool from `60^(@)C` to `30^(@)C` The temperature of the surroundings is `20^(@)C` .

Explanation

To solve the problem of how long it takes for a body to cool from \(60^\circ C\) to \(30^\circ C\) given that it cools from \(80^\circ C\) to \(50^\circ C\) in 5 minutes, we can use Newton's Law of Cooling.

### Step-by-Step Solution:

1. **Identify the temperatures and time for the first cooling process:**
- Initial temperature (\(T_1\)) = \(80^\circ C\)
- Final temperature (\(T_2\)) = \(50^\circ C\)
- Time taken (\(t\)) = 5 minutes
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