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A ring consisting of two parts ADB and A...

A ring consisting of two parts `ADB` and `ACB` of same conductivity k carries an amount of heat `H` The `ADB` part is now replaced with another metal keeping the temperature `T_91)` and `T_(2)` constant The heat carried increases to `2H` What should be the conductivity of the new `ADB` Given `(ACB)/(ADB)=3`
.

A

`(7)/(3)K`

B

`2K`

C

`(5)/(2)K`

D

`3K`

Text Solution

Verified by Experts

The correct Answer is:
A
`(dQ)/(dt) = (KA d theta)/("arc length")` .
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