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Two identical rods are connected between two containers. One of them is at `100^(@)C` containing water and another is at `0^(@)C` containing ice. If rods are connected in parallel then the rate of melting of ice is `q_(1)g//s` . If they are connected in series then teh rate is `q_(2)g//s` . The ratio `q_(2)//q_(1)` is

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Verified by Experts

The correct Answer is:
4

`("Temperature difference")/("Thermalresistance")=L((dm)/(dt))`
`(dm)/(dt)prop(1)/("Thermalresistance"),qprop(1/(R))`
The rods are in parallel in the first case and they are in series in the second case `(q_(1))/(q_(2))=(2R)/((R//2))=4` .
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