Two spherical bodies A (radius 6cm) and B (radius 18cm) are at temperature `T_(1)` and `T_(2)` respectively The maximum intensity in the emission spectrum of A is at `500 nm` and in that of `B` is at `1500nm` considering them to be black bodies, what will be the ratio of total energy radiated by `A` to that of `B` .

Answer

9

Explanation

`9 (T_(1)) (500 nm) =T_(2) (1500nm), T_(1) =3T_(2)`
`E_(A) = sigma. 4pi (6cm)^(2) (T_(1))^(4)`
`E_(B) = sigma. 4pi (18 cm)^(2) (T_(1))^(4)`
`(E_(A))/(E_(B))=((1)/(3))^(2)xx(3)^(4)=9` .