A metal rod AB of length 10x has its one end A in ice at `0^@C`, and the other end B in water at `100^@C`. If a point P one the rod is maintained at `400^@C`, then it is found that equal amounts of water and ice evaporate and melt per unit time. The latent heat of evaporation of water is `540cal//g` and latent heat of melting of ice is `80cal//g`. If the point P is at a distance of `lambdax` from the ice end A, find the value `lambda`. [Neglect any heat loss to the surrounding.]

Answer

9

Explanation

`(dm_(ice))/(dt)=(dm_(vapour))/(dt)`
`Q_(1) = (KA400)/(t) =mxx80`
`Q_(1) = (KA400)/(t)=mxx80`
`Q_(1)=(KA(400-1000)t)/((10-lambda)x)t=mxx540`
Dividing both `lamda =9`
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