Two rods one is semi circular of thermal conductivity `K_(1)` and otheir is straight of thermal conductivity `K_(2)` and of same cross sectional area are joined as shown in the The points `A` and `B` are maintained at same temperature difference. If rate of flow of heat is same in two rods then `K_(1)//K_(2)` is
.

Options

A. `2:pi`
B. `1:2`
C. `pi:2`
D. `3:2`

Answer

C

Explanation

`((Q)/(t))_("semicircularrod")=((Q)/(t))_("straightrod")`
`(K_(1)A(Deltatheta))/(pir)=(K_(2)A(Deltatheta))/(2r)`
r =` radius of semi circle .