A diatomic ideal gas is compressed adiabatically to 1/32 of its initial volume. If the initial temperature of the gas is `T_i` (in Kelvin) and the final temperature is a `T_i`, the value of a is

Answer

D

Explanation

`T_(i)v^(gamma-1)=alphaT_(I)((1)/(32)V)^(gamma-1)`
`alpha=(32)^((7)/(5)t)=(32)^(2/(5))=(2^(5))^(2/(5))=4` .