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Two moles of an ideal monoatomic gas is taken through a cycle ABCA as shown in the P-T diagram. During the process AB , pressure and temperature of the gas very such that `PT=Constant`. It `T_1=300K`, calculate

(a) the work done on the gas in the process AB and
(b) the heat absorbed or released by the gas in each of the processes. Give answer in terms of the gas constant R.

Text Solution

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The correct Answer is:
A, B

(a) `PT` =const. `=2p_(1)t_(1)=600p_(1)`
`V=(nRT)/(P)=(nRT^(2))/(600P_(1)) W = int_(A)^(B)Pdv int_(2T_(1))^(T_(1)) (600P_(1))/(T)xx(2nRT)/(600P_(1))dT`
`:. W=- 1200 R - 1200 R`
(b) For process `ArarrB DeltaU=(2R)/(gamma-1)(T_(1)-2T_(1))=-900R`
`DeltaQ=DeltaU+W=-2100R` For process `BrarrC`
`DeltaQ=nC_(P)DeltaT=2xx(5)/(3)xx(3)/(2)RT_(1)=1500 R`
For process `CrarrA DeltaQ=DeltaW=nRT//n((2P_(1))/(P_(1)))=nR2T_(1)ln2`
`=1200 Rln2`
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