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A copper block of mass 5kg slides down a...

A copper block of mass `5kg` slides down along a rough inclined plane of inclination `30^(@)C` with a constant speed. The increase in the temperature of the block as it slide down through `100cm` assuming that the loss of mechanical energy goes into copper block as thermal energy. (specific heat of copper
`420 Jkg^(-1)K^(-1),g=10ms^(-2))`

A

`1.19xx10^(-3) .^(@)C`

B

`2.38xx10^(-3) .^(@)C`

C

`1.19xx10^(-2) .^(@)C`

D

`2.38xx10^(-2) .^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
C
`(1)/(2)mv^(2)=JmSDeltaT,(1)/(2)xx2glsin theta=JSDeltaT`
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