1672cal of heat is given to one mole of ...

`1672cal` of heat is given to one mole of oxygen at `0^(@)C` keeping the volume constant. Raise in temperature is `(c_(p)=0cal//gm^(0)k and R=2cal//"mole"//K)`

`33.6^(@)C`

`36.3^(@)C`

`63.3^(@)C`

`334.4^(@)C`

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The correct Answer is:

`DeltaQ_(V)=nC_(V)DeltaT`

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