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One mole of an ideal gas with gamma=1.4 ...

One mole of an ideal gas with `gamma=1.4` is adiabatically compressed so that its temperature rises from `27^(@)C` to `34^(@)C` . The change in the internal energy of the gas is `(R=8.3J mol^(-10k^(-1)))`

A

`-166J`

B

`166J`

C

`168J`

D

`-168J`

Text Solution

Verified by Experts

The correct Answer is:
B
`dU=(nR(T_(1)-T_(2)))/(gamma-1)`
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