The work function of a metal is `3.0eV`.It is illuminated by a light of wave length `3xx10^(7)m`.Calculate i) threshold frequency, ii)the maximum energy of photoelectrons, iii) the stopping potential. `(h=6.63xx10^(-34)Js` and `c=3xx10^(8)ms^(-1))`

Explanation

To solve the problem, we will follow these steps:

### Given Data:
- Work function (φ) = 3.0 eV
- Wavelength (λ) = \(3 \times 10^{-7}\) m
- Planck's constant (h) = \(6.63 \times 10^{-34}\) Js
- Speed of light (c) = \(3 \times 10^{8}\) m/s

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