Home
Class 12
PHYSICS
A metal of work function 4eV is cexposed...

A metal of work function `4eV` is cexposed to a radiation of wavelegth `140xx10^(-9)m`. Find the stopping potential.

Text Solution

Verified by Experts

`E=(hc)/lambdaE=(6.62xx10^(-34)xx3xx10^(8))/(140xx10^(-9)xx1.6xx10^(-19))eV=8.86eV`
work function `W_(0)=4eV`
`eV_(0)=E-W_(0)=8.86-4=4.76eV`
`:.` Stopping potential `V_(0)=4.86V`
Promotional Banner

Topper's Solved these Questions

  • DUAL NATURE

    NARAYNA|Exercise C.U.Q|108 Videos

  • DUAL NATURE

    NARAYNA|Exercise LEVEL-I (C.W)|16 Videos

  • DUAL NATURE OF RADIATION AND MATTER

    NARAYNA|Exercise ASSERTION AND REASON|15 Videos

  • ELECTRIC CHARGES AND FIELDS

    NARAYNA|Exercise EXERCISE -4|43 Videos

Similar Questions

Explore conceptually related problems

A metal surface of work function 1.07 eV is irradiated with light of wavelength 332 nm . The retarding potential required to stop the escape of photo - electrons is

The photoelectric work function for potassium is 2 eV . The light of wavelength 3.6 xx 10^(-7) m falls on potassium . The stopping potential is

An electron of work function 1.4 eV is emitted with a velocity 5 xx 10^(6) m/s . The wavelength of the incident radiation is

In the arrangement shown if Fig. y=1.0mm , d=0.24mm and D=1.2m . The work function of the material of the emitter if 2.2 eV. Find the stopping potential V needed to stop photocurrent (in xx10^(-1) V).

The work function of a metal is 4.0 eV . If the metal is irradiated with radiation of wavelength 200 nm, then the maximum kinetic energy of the photoelectrons would be about.

The work function of a metal is 3.0eV .It is illuminated by a light of wave length 3xx10^(7)m .Calculate i) threshold frequency, ii)the maximum energy of photoelectrons, iii) the stopping potential. (h=6.63xx10^(-34)Js and c=3xx10^(8)ms^(-1))

0.24eV of energy is required to stop photoelectron emitted by radiation of wavelength 2480 Å . Find work function of metal used?

A radiation is incident on a metal surface of work function 2.3 eV. The wavelength of incident radiation is 60 nm, then the number of photoelectrons is

Light of wavelength 3320 Å incidents on metal surface (work function = 1.07 eV ). To stop emission of photo electron, retarding potential required to be -

The stopping potential for the photoelectrons emitted from a metal surface of work function 1.7 eV is 10.4 V. Find the wavelength of the radiaiton used. Also, identify the energy levels in hydrogen atom, which will emit this wavelength.

NARAYNA-DUAL NATURE-LEVEL-II (H.W)
  1. A metal of work function 4eV is cexposed to a radiation of wavelegth 1...

    Text Solution

    |

  2. When a metal surface is illuminated by a monochromatic light of wave-l...

    Text Solution

    |

  3. Ultraviolet light of wavelength 800 A and 700 A when allowed to fall ...

    Text Solution

    |

  4. In a photoelectric effect experiment, photons of energy 5eV are incide...

    Text Solution

    |

  5. The number of photons emitted per second by a 62W source of monochroma...

    Text Solution

    |

  6. Photons of frequencies 2.2xx10^(15) Hz and 4.6xx10^(15) Hz are inciden...

    Text Solution

    |

  7. If stopping potentials corresponding to wavelengths 4000A and 4500A ar...

    Text Solution

    |

  8. In a photoelectric experiment anode potential is ploted against plate ...

    Text Solution

    |

  9. An electron moves with a speed of sqrt3/2c. Then its mass becomes…. Ti...

    Text Solution

    |

  10. Photons of energy 2.0eV fall on a metal plate and release photoelectro...

    Text Solution

    |

  11. A proton when accelerated through a p.d of V volt has wavelength lambd...

    Text Solution

    |

  12. The momentum of photon of electromagnetic radiation is 3.3xx10^(-29)kg...

    Text Solution

    |

  13. If the energy of a particle is reduced to one fourth, then the percent...

    Text Solution

    |

  14. The de Broglie wavelength associated with an electron of velocity 0.3c...

    Text Solution

    |

  15. The two lines A and B in fig. show the photo electron of de Broglie wa...

    Text Solution

    |

  16. The uncertainity in the position of a particle is equal to the de-Brog...

    Text Solution

    |

  17. If the uncertainty in the position of proton is 6xx10^-8m, then the mi...

    Text Solution

    |

  18. From Davisson-Germer experiment an alpha particle and a proton are acc...

    Text Solution

    |